Chapter 11 Homework and Learning Objectives
Chapter 11 Homework
Nomenclature(CH7), writing a balanced chemical equation(CH9), and the mole concept(CH10) will be used throughout CH 11. Master chapter 7,9, and 10 to be successful on chapter 11.
-Read 11.1 and take notes, complete the sample and practice problems in the reading, Complete 11.1 WS’s
-Read 11.2 and take notes, complete the sample and practice problems in the reading, Complete 11.2 WS’s
-Read 11.3 and take notes, complete the sample and practice problems in the reading, Complete 11.3 WS’s
-Rice Krispy Lab
-Stoich Football Lab
-Chapter Review pg. 376 1-22 all, 29-58 (sampling of each kind of stoich problem, mole to mole, gram to gram, etc)
Test 11
Chapter 11 Learning Objectives
11.1
Stoichiometry- apply the mole concept (molar ratios) to relate quantities of reactants and products in a balanced chemical equation
1. Write a balanced chemical equation.
2. The Given (reactant or product) must be converted to moles. If moles is not given then convert the given unit to moles first before doing stoichiometry.
3. Use the coefficients in the balanced equation to compare reactants and products (Stoich it!). The coefficients in the balanced equation represent molar ratios. Stoichiometry is used to solve for moles of reactant and or product. By doing stoichiometry you can determine how much reactant is needed and or how much product is produced in a chemical reaction. Determine the molar ratio between reactants and products by using the coefficients in the balanced chemical equation. Coefficients = Molar ratios
4. Use dimensional analysis to set up the problem and solve. (UNITS MUST CANCEL)
5. Convert the final answer to the desired unit.
11.2 See flow charts on pg. 354-355
Given convert to moles, find molar ratios and solve for moles unknown, convert moles of your unknown to desired unit
Page 363 How silk is obtained. A chemical reaction that takes place by the silk worm, silk worm feeds on the mulberry leaves, secrete a liquid that forms a cocoon, the silk thread is obtained from the cocoon. Each cocoon produce 1.6 km of thread, 100 cocoons to make a tie, 600 cocoons to make shirt,
11.3 Limiting Reactants and Percent Yield
-excess reactant
-theoretical yield
-actual yield
To find L.R. set up two equations. Compare Reactant A to product A, compare Reactant B to product A. The reactant that produces less product is the limiting reactant.
The limiting reactant will limit the amount of product that can be made. The limiting reactant will be completely used up by the reaction, the other reactants will have some amount left over, the left overs are called excess reactants.
Limiting Reactant Simulation (non-chemistry example)
Pg. 371 Percent Yield= actual yield/theorectical yield(expected yield) x 100
Expected or theoretical yield –the amount of product that should be produced based on calculations. Doing stoichiometry, using the balanced chemical eqn.
Actual yield- The amount of product that is actually obtained from the chemical reaction. Completing the lab and weighing your product. (Given to you)
What are some reasons why actual yield is often lower than expected yield?
Pg. 373 Read an explosive mistake, charcoal lighter on coals. The combustion of heptane.
Virtual Lab Assignment:
Prelab-
Read Encyclopedia of Earth Article on Combustion
Combustion Stoichiometry Virtual Lab
Acid/Base Universal Indicator Lab
Visit the Nomenclature web-sites below.
Rules for Naming Inorganic Compounds One error on the table Hg2 2 is called Mercury (I) or mercurous
Use this link to practice IC/roman numeral usage: Nomenclature of Simple Compounds- Transition Metals
Use this link to practice IC and CC: Nomenclature of Simple Compounds- Formulas to Names
Use this link to practice IC and CC: Nomenclature of Simple Compounds- Names to Formulas
